Answer by Henry for Expected winning score in a round robin tournament
You can get a good approximation by making the correct assumption that each player's score is a binomial distribution with parameters $99$ and $\frac12$ and the slightly wrong assumption that each...
View ArticleAnswer by Lourrran for Expected winning score in a round robin tournament
99 is a pretty big number, we can use normal distribution. Average is 49.5, Standard-deviation is $\frac{\sqrt{99}}{2}=4.975$ ; Excel gives the result :loi.normale(56; 49.5;4.975;True)=0.9090% of...
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Answer by Gabriel Romon for Expected winning score in a round robin tournament
Simulations reveal that the expected value of the highest score is close to $62$ and that of the lowest score is close to $37$.Here is the code for a million trials.import numpy as np n_players =...
View ArticleExpected winning score in a round robin tournament
Suppose you have a tournament consisting of 100 players in which each player plays each other player exactly once. In any given match, the chance of either playing winning is equally likely, and there...
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